Math 1 · Lesson 6 · part 6 of 6

Practice Problems

Try them, get help one step at a time, then print how it went.

Warm-up: read, test, flip

Four short ones before the real solving. Say the property out loud as you type.

Practice: try it, then get help one step at a time

Try each problem yourself first. Hint gives a nudge, Show next step shows one worked step at a time, Reveal answer checks, and Hide help / start over clears the card. Every problem asks two things: did the sign flip, and what is the solution. The problems climb from one move to a full solution you name line by line.

My results

Finished the practice? Print a page that shows each question, what you typed or chose, the correct answer, and how it went. Good for showing a teacher or keeping in a folder.

Exit ticket

On paper or an index card. Use the math word and the plain-English word.

  1. Read −4 > −9 out loud. Which number is the gator eating, and why is that the right one?
  2. Solve 2 - 3x ≤ 11. Show Step 1, name the property on every line, say where the sign flips, and check three numbers.
  3. Solve 5x + 1 > 2x + 10. Which x term did you move, and did you need to flip?
  4. A friend solved −2x < 8 and wrote x < −4. Use one test number to show the friend it is wrong, then write the right answer.
Check your exit ticket
  1. Negative four is greater than negative nine. The gator eats the −4, because −4 is to the right of −9 on the number line, so it is the bigger number. Being closer to zero on the negative side means bigger.
  2. Step 1: 2 + (−3)x ≤ 11 (subtracting 3x is adding its additive inverse, the opposite). Add −2 to both sides by the addition property of inequality (add the same thing to both sides, and the sign stays the same): (−3)x ≤ 9. Multiply both sides by −13, the multiplicative inverse (the reciprocal) of −3. That is the multiplication property of inequality for a negative number, so this is where the sign flips: x ≥ −3. Check: x = 0 gives 2 ≤ 11, true. x = −3, the boundary, gives 2 + 9 = 11 ≤ 11, true, so it is included. x = −4 gives 2 + 12 = 14 ≤ 11, false.
  3. Step 1: 5x + 1 > 2x + 10 has nothing to rewrite. The coefficients (the numbers on the variables) are 5 and 2, so move the 2x: add −2x to both sides, giving 3x + 1 > 10 by the distributive property run backwards (factoring, pulling out what the terms share). Add −1 to both sides: 3x > 9. Multiply both sides by 13, positive, no flip: x > 3. No flip was needed because the x term we kept has a positive coefficient (the number on the variable).
  4. Test x = 0 in the original: −2 × 0 = 0, and 0 < 8 is true, so 0 must be a solution. But 0 < −4 is false, so the friend's answer leaves out a number that works. The friend multiplied both sides by −12, a negative number, and forgot to flip. The right answer is x > −4, and 0 > −4 is true.

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