Math 1 · Unit 8 · Lesson 4 · part 2 of 5

Kevin and Joseph: $5 a month, or 3% a month?

Two friends each invest $100.

Kevin and Joseph: $5 a month, or 3% a month?

Two friends each invest $100. They get paid in different ways.

Kevin: $5 every month

The same dollars added each month: a constant difference. Lines add.

K(m) = 100 + 5m

This is simple interest: $5 is 5% of the original $100, paid every month on the principal only.

Joseph: 3% every month

The same percent each month: multiply by 1 + 0.03 = 1.03, a constant ratio. Exponentials multiply.

J(m) = 100(1.03)m

This is compound interest: each month's 3% is on everything in the account.

Who would you rather be? Kevin's 5% sounds better than Joseph's 3%, and for a long time it is.

monthKevin: 100 + 5mJoseph: 100(1.03)mahead
0$100.00$100.00tie
6$130.00$119.41Kevin
12$160.00$142.58Kevin
24$220.00$203.28Kevin
30$250.00$242.73Kevin
32$260.00$257.51Kevin
33$265.00$265.23Joseph
36$280.00$289.83Joseph
48$340.00$413.23Joseph

After two years (24 months) Kevin is well ahead, $220.00 to $203.28. That surprises people. But look at months 32 and 33: Joseph catches up and passes him, and by month 48 Joseph is ahead by more than $70. Run the race yourself.

The big idea: multiplying always passes adding, sooner or later. A line adds the same amount forever. An exponential's step keeps growing, because it is a percent of a growing balance. So a quantity that grows by multiplying eventually exceeds one that grows by adding, no matter how far behind it starts, and once it passes it stays ahead.

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